Quadratic Discriminant Calculation
If you need to look for the Discriminant of a quadratic equation, for example x2 + 5x + 4 = 0 , you will need to open Quadratic Solver page in Orimath Quadratic Solver.
Check the Type of Equation that you wish to use and enter the numbers in your equation into the textboxes in the right side.
Don't forget to check Discriminant in the lower box.
Then Click as HTML button. Clicking the as HTML button will tell Orimath Quadratic Solver to write the answers for the problems along with the steps required to get the answers in HTML format. This will allow the program to show you the answer in easily readable format.
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Answer by Orimath Quadratic Solver :
Question Number 1 :
For this equation x2 + 5x + 4 = 0 , answer the following questions :
Answer Number 1 :
The equation x2 + 5x + 4 = 0 is already in ax2+bx+c=0 form.
Then we can imply that the value of a = 1, b = 5, c = 4.
| | Use the formula, Discriminant = b2-4ac to get the answers. | | Since the value of a = 1, b = 5 and c = 4 are known, | | we only have to subtitute those values into Discriminant = b2-4ac. | | So Discriminant = (5)2 - 4 (1) (4) | | Which is the same as Discriminant = 25-16 | | So the answers is : Discriminant = 9 | | Positive Discriminant value, means that f(x) = x2 + 5x + 4 is going to intersect x axis in two points. |
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Changing the Name of the Variables
Sometimes the quadratic equation problems are not presented to you in x. There are some possibility that the equation is presented in other variables, lets take t2 + 5t + 4 = 0 as an example.
In this case you will need to change x with t, and click Change the variable button. Then click as HTML to tell Orimath Quadratic Solver to solve the problem for you and tell you the steps required to get the answer.
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Answer by Orimath Quadratic Solver :
Question Number 2 :
For this equation t2 + 5t + 4 = 0 , answer the following questions :
Answer Number 2 :
The equation t2 + 5t + 4 = 0 is already in ax2+bx+c=0 form.
By matching the constant position, we can derive that the value of a = 1, b = 5, c = 4.
| | You only have to use Discriminant = b2-4ac to solve this problem. | | Since the value of a = 1, b = 5 and c = 4 are known, | | we can subtitute the value of a and c into Discriminant = b2-4ac. | | Which produce Discriminant = (5)2 - 4 (1) (4) | | Which can be turned into Discriminant = 25-16 | | So the answers is : Discriminant = 9 | | Positive Discriminant value, means that f(t) = t2 + 5t + 4 is going to intersect t axis in two points. |
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Problems related to Quadratic Equations that Orimath Quadratic Solver is capable to do :
Problems related to Quadratic Functions that Orimath Quadratic Solver is capable to do :
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