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Solving Quadratic Equations



There are three ways in Orimath Quadratic Solver available for you to use. In the problem presented to you, you might be asked to use either quadratic formula, factorization or completing the square. Orimath Quadratic Solver can show you how to use any of them to solve a quadratic polynomial equation.


All you have to do is to check any check boxes related to solving quadratic equation ( see the picture above ). Then click as HTML to tell Orimath Quadratic Solver to solve the problem for you and tell you the steps required to get the answer.






Answer by Orimath Quadratic Solver :
Question Number 1 :
For this equation x2 + 5x + 4 = 0 , answer the following questions :
A.
Find the roots using Quadratic Formula ! !
B.
Use factorization to find the root of the equation !
C.
Use completing the square to find the root of the equation !

Answer Number 1 :
The equation x2 + 5x + 4 = 0 is already in ax2+bx+c=0 form.
As the value is already arranged in ax2+bx+c=0 form, we get the value of a = 1, b = 5, c = 4.

By using abc formula the value of x as defined by
x[1,2] =
-b (b2-4ac)
2a
Since a = 1, b = 5 and c = 4,
we just need to subtitute the value of a,b and c in the abc formula.
So x[1,2] = - (5) (5)2 - 4 (1) (4) )
2 (1)
Which produce x[1,2] = -5(25 - 16)
2
So x[1,2] = -59
2
We got x1 = ( -5 + 3 )/(2) and x2 = ( -5 - 3 )/(2)
So we got the answers as x1 = -1 and x2 = -4
x2 + 5x + 4 = 0 , factorize the left hand side.
( x + 1 ) ( x + 4 ) = 0
We get following answers x1 = -1 and x2 = -4
x2 + 5x + 4 = 0 ,divide both side with 1
Which result in x2 + 5x + 4 = 0 ,
The coefficient of x is 5
We have to use the fact that ( x + q )2 = x2 + 2qx + q2 , assume that q = 5/2 = 2.5 , and q2 = (2.5)2 = 6.25
Next, we have to separate the constant to form x2 + 5x + 6.25 - 2.25 = 0
And it is the same with ( x + 2.5 )2 - 2.25 = 0
Which can be turned into (( x + 2.5 ) - 1.5 ) (( x + 2.5 ) + 1.5 ) = 0
By opening the brackets we will get ( x + 2.5 - 1.5 ) ( x + 2.5 + 1.5 ) = 0
Do the addition/subtraction, and we get ( x + 1 ) ( x + 4 ) = 0
So we have the answers x1 = -1 and x2 = -4





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